From the top of a hill the angle of depression of two consecutive kilometre stones due east are found to be 30 degree and 45 degree. find the height of the hill
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▶ Answer :
Height of the Hill is 1.36 km.
▶ Step - By - Step Explanation :
Let AB is the height of the hill and two stones are C and D respectively where depression is 45° and 30° ,
▶ Given : Distance Between C and D = 1 km
Now, In right angled ∆ABC
tan 45° = AB / BC
1 = AB/ BC
•°• BC = AB. -------(A)
Again , In right angled ∆ABD
tan 30 ° = AB / BC + CD
=> 1/√3 = AB / AB+ CD [ •°• AB = BC ]
=> 1/√3 = AB/ AB + 1
=> 1/ 1.732 = AB / AB + 1
=> 1.732AB = AB + 1
=> 1.732AB - AB = 1
=> 0.732AB = 1
=> AB = 1/0.732
=> AB = 1.36 Metres
Hence , Required Height of the Hill is 1.36 km
Height of the Hill is 1.36 km.
▶ Step - By - Step Explanation :
Let AB is the height of the hill and two stones are C and D respectively where depression is 45° and 30° ,
▶ Given : Distance Between C and D = 1 km
Now, In right angled ∆ABC
tan 45° = AB / BC
1 = AB/ BC
•°• BC = AB. -------(A)
Again , In right angled ∆ABD
tan 30 ° = AB / BC + CD
=> 1/√3 = AB / AB+ CD [ •°• AB = BC ]
=> 1/√3 = AB/ AB + 1
=> 1/ 1.732 = AB / AB + 1
=> 1.732AB = AB + 1
=> 1.732AB - AB = 1
=> 0.732AB = 1
=> AB = 1/0.732
=> AB = 1.36 Metres
Hence , Required Height of the Hill is 1.36 km
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