From the top of a lighthouse 75 m high, the angles of depression of two ships are observed to be 30ᵒ and 45ᵒ respectively. if one ship is directly behind the other on the same side of the lighthouse then find the distance between the two ships.
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in triangle ACD
tan 30=75lbc
1/root3=75/bc
by cross multiplication
bc=75root3
in triangle ABD
tan45=75/bd
1=75/bd
by cross multiplication
bd=75
cd=75root3-75
cd=75(root3-1)
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hey,hope this will help u
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