From the top of a lighthouse, an observer looking at a ship makes angle of
depression of 60°. If the height of the lighthouse is 90 metre, then find how far
the ship is from the lighthouse. ( 3 =1.73)
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Let AB be the height of the lighthouse,
∴ AB = 90 metres [Given]
The point 'C' be the position of the ship,
∴ ∠ ACB = 600
tan 600 = Opposite side of 600 / Adjacent side of 600
∴ tan 600 = AB / BC
∴ √3 = 90/BC
∴ BC = 90/√ 3
∴ BC = (90/√3)× √3/√3
∴ BC = 30√3
∴ BC = 30× 1.73
∴ BC = 51.9 m.
∴ The ship is 51.9 m away from the lighthouse.
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