Question

From the top of a lighthouse, the angles of depression of two ships on the opposite sides of it are observed to be a and B. If the height of the lighthouse be h metres and the line joining the ships passes through the foot of the lighthouse, show that the distance between the ships is
$\sf \: \frac{h(tan \: \alpha + tan \: \beta )}{tan \: \alpha + tan \: \beta} \: meters$

→ Spam answers will be deleted.
Don't be greedy for points ⚠️ ⚠️

→ Quality answers needed.​​

Answer 1

Step-by-step explanation:

your answer in the pic hope it helps u

Answer 2

$\huge\boxed{ \blue{ \mathfrak{\: Correct \: Question:-}}}$

• From the top of a lighthouse, the angles of depression of two ships on the opposite sides of it are observed to be a and B. If the height of the lighthouse be h metres and the line joining the ships passes through the foot of the lighthouse, show that the distance between the ships is $\sf \: \frac{h(tan \: \alpha + tan \: \beta )}{tan \: \alpha\:tan \: \beta} \: meters \\$

$\sf$

$\huge\boxed{ \blue{ \mathfrak{\: Answer:-}}}$

Hence, the distance between the ships is

$\sf \: \frac{h(tan \: \alpha + tan \: \beta )}{tan \: \alpha \: tan \: \beta }$

$\sf$

Answer refers in the attachment.

It helps you.