Question

From the top of a minar 30 mts. heigh, the angles of depression of the top and bottom of a tower are 30° and 60° respectively. Find the height of the tower.
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\huge\boxed{Answer:20cm}$

Let the height of tower be H

Given that :-

• From the top of a minar 30 mts. heigh, the angles of depression of the top and bottom of a tower are 30° and 60° respectively.

To find :-

• the height of the tower.
• the height of the tower.

The top and bottom of a tower are 30° and 60° respectively.

•°• In figure : AC represents height of minar and AE = DB represe nts height of height of tower .

$\boxed{A.T.Q}$

In Δ ABC

tan 60 = AB / 30

AB =  30 / √ 3 m  OR 10 √ 3

In Δ C.D.E

tan 30 = EC / DC

But DC = AB =  30 √ 3 m

1 / √ 3 = EC /  10 √ 3

EC = 10 m

Now , replace by H as :

h = AC - EC  ( AC is minar's height )

H = 30 - 10 m

H = 20 m

Hence , the  height of tower would be 20 m.