From the top of a platform 7m high, the angle of elevation of a tower was 30°. If the platform ws positioned 50√3 away from the tower, how tall was the tower?
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This is a question on Trigonometric ratios.
To answer this question you need to draw the diagram.
When you draw the diagram you will get a rectangle of sides 7 m by 50 m and a right angled triangle with a base of 50 m and an angle of 30° on the base.
From the diagram the height of the tower is :
= h + 7
To get h we will use trigonometric ratio Tan.
H = 50 Tan 30 = 28.87 m
The height of the tower is thus :
28.87 + 7 = 35.87 m
Find the diagram in the image attached.
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The height of The tower is:
H + 7
To get H we will use trigonometric ratio Tan.
H = 50 Tan 30 = 28.87 m
The height of the tower is Thus:
28.87 + 7 = 35.87 m.
H + 7
To get H we will use trigonometric ratio Tan.
H = 50 Tan 30 = 28.87 m
The height of the tower is Thus:
28.87 + 7 = 35.87 m.
Attachments:
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