from the top of a pole of height 26 m the angle of depression of the top of a house at a distance of 15 root 3 metre lying in front of the pole is observed and found to be 30 degree what must be the height of the house find it
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Let the height of the pole be h and the distance between the pole and tower be x.
It can be observed that,
tan60
∘
=
x
50
3
=
x
50
x=
3
50
And,
tan45
∘
=
x
50−h
1=
x
50−h
50−h=x
50−h=
3
50
h=50−
3
50
h=
3
50(
3
−1)
h=21.1m
Therefore, the height of the pole is 21.1m
HOPE IT HELPS YOU
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Answered by
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Step-by-step explanation:
Let the height of the pole be h and the distance between the pole and tower be x.
It can be observed that,
tan60
∘
=
x
50
3
=
x
50
x=
3
50
And,
tan45
∘
=
x
50−h
1=
x
50−h
50−h=x
50−h=
3
50
h=50−
3
50
h=
3
50(
3
−1)
h=21.1m
Therefore, the height of the pole is 21.1
Attachments:
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