From the top of a tower 100 m high, the angles of depression of the top and bottom of a pole standing on the same plane as the tower are observed to be 300 and 450 respectively. Find the height of the pole. (√3= 1.732)
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tan 30° =100-h/x tan 45°=100/x
1/√3 =100-h/x 1=100/x
x/√3=100-h x=100
100/√3=100-h
100√3/3=100-h
100-100√3/3=h
-100*1.732+300/3=h
300-173.2/3=h
126.8/3=h
42.26=h
1/√3 =100-h/x 1=100/x
x/√3=100-h x=100
100/√3=100-h
100√3/3=100-h
100-100√3/3=h
-100*1.732+300/3=h
300-173.2/3=h
126.8/3=h
42.26=h
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