Question

from the top of a tower 100m height a man observes two cars on the opposite side of tower is angle of depression 30 degree and 45 degree respectively find the speed distance between the car

Answer 1

Answer:

solved below

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the observer be D and the cars be A and B.

Therefore, the difference between the cars speed distance will be (x-y).

In ∆BCD

tan 45°= CD/BC

1= 100/ y

y= 100m .....(1)

Now, In ∆ACD

tan 30°= CD/AC

1/√3 = 100/ X

x= 100√3

x= 100× 1.73

= 173 m .....(2)

therefore, from (1) & (2)

the cars speed distance = x- y

= 173-100

= 73m.