from the top of a tower 24meter high the angles Of depression of the top and the foot of a pole are observed to be 45°and 60°respectively find the hight of the pole
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∠BQM=45∘ , as from the figure we can see that angle of depression of the top of the pole are alternate interior angles, and alternate interior angles are equal. We know that tan45∘=1 and tan60∘=√3 . Therefore, the height of the pole is 50(√3−1)√3meters .
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