Question

From the top of a tower 50√3 m high the angles of depression of the top and bottom of a pole are observed to be 45 degree and 60 degree respectively. Find the height of the pole.

Answer 1

Answer:

Here CD is the tower and AB is the pole.

In △CDB, CD/BC = tan 60°

=> 50m/BC = √3

=> BC = 50/√3m

AE = BC

AE = 50/√3m

In △ADE, DE/AE = tan 45°

=> DE/50/√3m = 1

=> DE = 50/√3m

so the height of the pole is 50/√3m

Answer 2

Height of the pole is 21.13 m.Step-by-step explanation:

Let EC be the tower of height 50 m and AB is the pole of height h.

Please find the attached figure.

In triangle EAD,  



In triangle EBC,



From (1) and (2)



Hence, height of the pole is 21.13 m.