Question

from the top of a tower 50 m high , the angle of depression of the top of the pole is 45 degrees and from the foot of the pole the angle of elevation of the top of the tower is 60 degrees . find the height of the pole if the pole and the tower stand on the same plane

Answer 1

Answer:

Height of the pole is 21.13 m.Step-by-step explanation:

Let EC be the tower of height 50 m and AB is the pole of height h.

Please find the attached figure.

In triangle EAD,  

$\tan45=\frac{50-h}{AD}\\\\AD=(50-h).......(1)$

In triangle EBC,

$\tan60=\frac{50}{BC}\\\\\sqrt3=\frac{50}{AD}\\\\\text{Since BC is equal to AD}\\\\AD=\frac{50}{\sqrt3}.......(2)$

From (1) and (2)

$(50-h)=\frac{50}{\sqrt3}\\\h=50-\frac{50}{\sqrt3}\\\\h=21.13$

Hence, height of the pole is 21.13 m.

Answer 2

Step-by-step explanation:

this may hlep u in question