from the top of a tower,80 m high from the ground,a stone is thrown in the horizontal direction with a velocity of 8m/s.the stone reaches the ground after a time t and falls at a distance of d from thr foot of the tower are...
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First we calculate the time of free fall, taking only the y component
S=80m u=0m/s
We use the formula s=ut+1/2gt^2
80=(0)+1/2(10)t^2 {taking g=10}
t^2=80/5=16
So t=4sec
Now we calculate the distance travelled in 4sec
We again use s=ut+1/2at^2
S=8*4+0 {a=0} {given u=8m/s}
So s=32m
So d = 32m
S=80m u=0m/s
We use the formula s=ut+1/2gt^2
80=(0)+1/2(10)t^2 {taking g=10}
t^2=80/5=16
So t=4sec
Now we calculate the distance travelled in 4sec
We again use s=ut+1/2at^2
S=8*4+0 {a=0} {given u=8m/s}
So s=32m
So d = 32m
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