Physics, asked by srichetan4142, 10 months ago

From the top of a tower a particle is thrown vertically downwards with a velocity of 10 metre per second the ratio of the distance covered by it in the third and second second of its motion is

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Answered by hiteshavi
8

Answer:

the ratio between distance covered in third sec and second sec is

s3:s2= 7:5

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Answered by proton08
1

just a formula putting qs

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