Physics, asked by abhinavbhardwajbth, 1 year ago

From the top of a tower a stone is thrown up and reaches the ground in time t1 . A second stone is thrown down with the same speed and reaches the ground in time t2. A third stone is released from rest reaches the ground in time t3 then,what is t3 equal to?

Answers

Answered by makeithrilyn
15

Answer:t3 = square root of t1 × t2

Explanation:

Answered by nvsakhil3339
0

Answer:

t3=√t1 t2

Explanation:

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