From the top of a tower ,a stone is thrown with a velocity of 20 m/s in upward direction at an angle 30 degree up with the horizontal.The stone strikes the earth after 4 sec of flight.Find height of tower and horizontal range of stone.(approximate values)
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11th
Physics
Motion in a Plane
Projectile Motion
A stone is thrown from the ...
PHYSICS
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Asked on December 26, 2019 by
Vinutha Maddela
A stone is thrown from the top of a tower at an angle of 30
0
up with the horizontal with a velocity of 16 m/s. After 4 seconds of flight it strikes the ground. Calculate the height of the tower from the ground and the horizontal range of the stone (g=9.8 m/s
2
)
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ANSWER
Given V=16m/s, time t=4s. Let height h, and Horizontal range R
Velocity in upward direction V
y
=Vsin(30
o
)=8m/s,
Velocity in horizontal V
x
=Vcos(30
o
)=8
3
In upward direction, Using s=ut+
2
1
at
2
⇒h=8×4−
2
1
×9.8×4
2
⇒h=−46.4 , Hence, Height=46.4m,
In horizontal direction, Range=V
x
×t
⇒R=8
3
×4=32
3
m, Hence Range is 32
3
m