Physics, asked by adityapratapsip789qd, 7 months ago

From the top of a tower ,a stone is thrown with a velocity of 20 m/s in upward direction at an angle 30 degree up with the horizontal.The stone strikes the earth after 4 sec of flight.Find height of tower and horizontal range of stone.(approximate values)​

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Answered by vasu71465
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Motion in a Plane

Projectile Motion

A stone is thrown from the ...

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Asked on December 26, 2019 by

Vinutha Maddela

A stone is thrown from the top of a tower at an angle of 30

0

up with the horizontal with a velocity of 16 m/s. After 4 seconds of flight it strikes the ground. Calculate the height of the tower from the ground and the horizontal range of the stone (g=9.8 m/s

2

)

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ANSWER

Given V=16m/s, time t=4s. Let height h, and Horizontal range R

Velocity in upward direction V

y

=Vsin(30

o

)=8m/s,

Velocity in horizontal V

x

=Vcos(30

o

)=8

3

In upward direction, Using s=ut+

2

1

at

2

⇒h=8×4−

2

1

×9.8×4

2

⇒h=−46.4 , Hence, Height=46.4m,

In horizontal direction, Range=V

x

×t

⇒R=8

3

×4=32

3

m, Hence Range is 32

3

m

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