Question

From the top of a tower of height 120 m, the angle of depression of an object lying in front
of the tower observed and found to be 60°. Find the distance between the object and the foot
of the tower​

Answer 1

Answer:

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Step-by-step explanation:

Let BE=h,AB=60−h,BC=ED

Distance between tower and building be ED=x

In ΔAED,tan60

∘

=

ED

AE

=

x

60

⇒

3

=

x

60

⇒x=20

3

m

In ΔABC,tan30

∘

=

BC

AB

=

20

3

60−h

⇒

3

1

=

20

3

60−h

⇒h=40m

solution

Answer 2

Step-by-step explanation:

From the top of a tower of height 120 m, the angle of depression of an object lying in front

of the tower observed and found to be 60°. Find the distance between the object and the foot

of the tower