Question

From the top of a tower of height 150 m the angles of depression of the
top and bottom of a pole are 30° and 45° respectively. Find
(i) how far the pole is from the bottom of a tower.
(ii) the height of the pole. Use root 3 = 1.732 ​

Answer 1

tan45=150/x

1=150/x

x=150m away from tower

(ii)tan30=x/150

$1 \div \sqrt{3} = x \div 150$

$\sqrt{3} x = 150$

$x = 150 \div \sqrt{3}$

$3 \times 5 \times 10 \div \sqrt{3}$

$50 \sqrt{3}$

$86.6$

now this can be subtracted by real height of tower

$150 - 86.6 = 63.4$