Question

From the top of a tower the angle of depression of an object on the horizontal ground is found to be 60 degree.on descending 20 m vertically downwards from the top of the tower, the angle of the depression of the object is found to be 30 degree.find the height of the tower.
can i get the answer fast plzz......
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Answer 1

Answer:

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Answer 2

Answer:

h = 30 m

Step-by-step explanation:

Let the height of tower be (x+20) m

Let the distance between foot of tower and object be 'y' m

tan 60 = $\sqrt{3\\}$ = $\frac{x+20}{y}$

y = $\frac{x+20}{\sqrt{3} }$ m ... (i)

tan 30 = $\frac{1}{\sqrt{3} }$ = $\frac{x}{y}$

y = $x\sqrt{3}$ m ... (ii)

(i) = (ii) ;

$\frac{x+20}{\sqrt{3} }$ = $x\sqrt{3}$

x + 20 = 3x

x = 10

Therefore, height of tower = x + 20 = 30 m

HENCE SOLVED

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