Question

From the top of a tree of height 13 m the angle of elevation and depression of the top
and bottom of another tree are 45° and 30° respectively. Find the height of the
second tree. (√3 = 1.732)​

Answer 1

height of second tree = 35.516 m

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Answer 2

The height of second tree is 35.516 m

Step-by-step explanation:

From the figure AB length of tree = 13 m

 $tan 30 =\frac{13}{AC}$

 AC = 13√3

BE = AC = 13√3

From the figure

$tan 45 = \frac{BE}{DE}$

BE = DE = 13 √3

Height of second tree

DE + CE = 13+ 13√3

    = 13(1+√3)

   =  13 * 2.732

= 35.516 m