Question

From the top of a vertical cliff 80m high the angles of depression of are 23° and 15° respectively. How far are the buoys apart? the angles of depression

Answer 1

Answer:120.6 m apart

Step-by-step explanation:

Let x1 = distance from bottom of cliff to first boat (at 25 degree angle of depression - from horizontal)

     x2 = distance from bottom of cliff to second boat (at 20 degree angle of depression - from horizontal)

     d = x2 - x1 = distance boats are apart from each other (m)

     h = height of cliff from water surface = 200 m    

x1 = h/[tan(25o)]  = (200 m)/(0.4663) = 428.9 m

     x2 = h/[tan(20o)]  = (200 m)/(0.3640) = 549.5 m

     d = x2 - x1 = 549.5 m - 428.9 m = 120.6 m apart PLEASE MARK ME AS BRAINLIESTi had caps on lol