Question

From the top of a wall of height 5 m. A ball is thrown horizontally with speed of 6 m/s. How far from the wall will the ball land?​

Answer 1

Given:

From the top of a wall of height 5 m, a ball is thrown horizontally with speed of 6 m/s.

To find:

Range of ball ?

Calculation:

• This is a case of AIR-GROUND PROJECTILE:

$h = u_{y}(t) + \dfrac{1}{2} g {t}^{2}$

$\implies \: 5 = 0(t) + 5 {t}^{2}$

$\implies \: {t}^{2} = 1$

$\implies \: t = 1 \: sec$

Now, range of ball will be :

$R = u_{x} \times t$

$\implies \: R = 6 \times 1$

$\implies \: R = 6 \: metres$

So, range of ball is 6 metres .

Answer 2

Given:

From the top of a wall of height 5 m, a ball is thrown horizontally with speed of 6 m/s.

To find:

Range of ball ?

Calculation:

• This is a case of AIR-GROUND PROJECTILE:

$h = uy( t) + \frac{1}{2} g + 2$

$= > 5 = 0(t) + 5 {t}^{2}$

$= > {t}^{2} = 1$

$= > t = 1sec$

1sec

Now, range of ball will be

$r = ux \times t$

$= > r = 6 \times 1$

$= > r = 6 \: metres$

So, range of ball is 6 metres