From the top of building 19.6m high,a ball Is projected horizontally. After how long does it strike the ground ? If the line joining the point of projected to the point,where hits the ground makes an angle of 45 degree with the horizontal,what is the initial velocity of the ball?
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Answer:
T = (2h/g)
= (2 x 19.6 m/(9.8 m/s2))
= 2 s.
U = 19.6/2
= 9.8 m/s^2
Hope this helps!
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