Question

from the top of cliff 20m high the angles of elevation of tip of a tower is found to be equal to angle of depressiom of foot of tower Height of tower is

Answer 1

Answer:

The height of the tower will be 40 meters.

Step-by-step explanation:

Let the angle of elevation = angle of depression = Ф

Let the cliff = AB

Tower = CD

E is a point corresponding to point A i.e. 20 m from base D

In triangle ABD,

tanФ = AB/BD

=> BD = AB/tanФ = 20/tanФ

=> AE = BD = 20/tanФ

In triangle AEC

tanФ = CE/AE

=> CE = AE x tanФ = 20/tanФ x tanФ = 20 m

Hence height of the tower = CD = CE + ED = 20 + 20 = 40 meters.

Answer 2

Answer: 40m

•Let the cliff be AB

and tower be CD

•CD = CE + ED

[Take a look at the attached image for the next steps]