Question

From the top of the building of 9 metre height the angle of elevation and depression of the top and foot of another house on the opposite side of the street are 30 degree and 60 degree respectively find the height of the opposite house on the width of the road​

Answer 1

Answer:

Height of the building = 12m

Step-by-step explanation:

let ED be the height of the building = 9m

In ∆ECD

tan60° = ED/CD

tan60° = 9/CD

CD = 9/√3 m

ED = BC = 9 m

CD = EB = 9/√3 m

In ∆ABE

tan30° = AB/EB

1/√3 = AB/EB

AB = 1/√3 x 9/√3 { since EB = 9/√3}

AB = 9/3

AB = 3 m

Height of the opposite house

= (AB + BC) m

= (3 + 9) m

= 12 m

Answer 2

dear such questions should be solved from books...