from the top of the building of height 30m, the angle of depression of the top and bottom of another building of height h meters are 30° and 60° respectively. find h
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The height of the another building, h is :
Given : height of the building = 30 cm, height of another building = h cm, angle of depression of the top = 30°, angle of depression of the bottom = 60°
• Suppose distance between two building is x
• In ∆ABC,
tan 30 = AB / BC = 30 - h / x
1/√3 = 30 - h / x
• x = 30√3 - √3h ....... 1
• In ∆ ADE,
tan 60 = AD / DE = 30 / x
√3 = 30 / x
• x = 30 / √3
Substitute value of x in equation 1
30 /√3 = 30√3 - h√3
30 = 30×3 - 3h
3h = 90 - 30 = 60
• h = 20 cm
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