From the top of the lighthouse, an observer
looks at a ship and finds the angle of
depression to be 30°. If the height of the
lighthouse is 100 metres, then find how far
the ship is from the lighthouse.
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Answer:
since the angle of depression is 30° the angle of elevation is also 30°(interior alternate angles)
let x be the distance of the ship from the lighthouse
tan30°=perpendicular/base
1/√3=100/x
x=100×√3
x=100×1.732
x=173.2
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