Question

from the top of the platform the angle of elevation of a tower was 30deg the tower was 45m height and horizontal distance between the platform and the tower was 40√3 what was the height of the platform

Answer 1

Answer:

5 m.

Step-by-step explanation:

From the diagram attached, AB is the platform and CD is the tower and it is given that distance between tower and platform AC=BE= 40√3 m.

Now, ∠DBE= angle of elevation of the tower from the top of the platform=30°

So, from ΔBED, tan 30°=DE/BE=DE/(40√3)

⇒DE=$40\sqrt{3}.\frac{1}{\sqrt{3} }$

⇒ DE= 40 m.

Now given that the height of the tower CD is 45 m.

So, CE= AB= height of platform = (CD-DE) = (45-40) =5 m. (Answer)