from the top of the tower 100 M high a man and observe two cars on the opposite side of the tower with angle of depression 30 degree and 45 degree respectively find the distance between the two cars
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1
tan30=p1/100
=1/√3=p1/100
p1=100/√3
also
tan45=p2/100
1=p2/100
p2=100
distance between two cars =p1+p2
=1/√3=p1/100
p1=100/√3
also
tan45=p2/100
1=p2/100
p2=100
distance between two cars =p1+p2
vivekrajSingh:
no wrong
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Distance between the two cars is 273m
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