Question

from the top of the tower 156.8 m high a projectile is thrown up with velocity of 39.2

Answer 1

horizontal --- Vx = 39.2 cos 30 = 33.95 m/3

Vertical --- initial Vy = 39.2 sin 30 = 19.6 m/s

vertical distance --- d(y) = h(0) + Vy t + (1/2)gt^2

0 = 156.8 + 19.6t - 4.9t^2

0 = -32 - 4t + t^2 = (t - 8)(t + 4) <<< t = 8 (t = -4 is not possible --- would involve time travel)

so time to hit the ground is 8 seconds <<< answer

horiz. distance = Vx t = 33.95 (8) = 271.6 m <<< answer