From the top of the tower 24m high,the angles of depression of the top and the foot of a pole are obserbed to be 45° ,60° respectively.Find the height of the pole.
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Answer:
Let the height of the pole be h and the distance between the pole and tower be x.
It can be observed that,
tan60∘=x50
3=x50
x=350
And,
tan45∘=x50−h
1=x50−h
50−h=x
50−h=350
h=50−350
h=350(3−1)
h=21.1m
Therefore, the height of the pole is 21.1m.

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