Question

from the top of the tower 30m height, the angle of depression of a car is 60 degrees.find the distance between the foot of the tower and the car

Answer 1

Let BE=h,AB=60−h,BC=ED

Distance between tower and building be ED=x

In ΔAED,tan60

∘

=

ED

AE

=

x

60

⇒

3

=

x

60

⇒x=20

3

m

In ΔABC,tan30

∘

=

BC

AB

=

20

3

60−h

⇒

3

1

=

20

3

60−h

⇒h=40m

solution