Question

From the top of the tower 50 M high the angle of depression of the top and the bottom of the pole are observed to be 45 degree and 60 degree respectively find the height of the pole

Answer 1

Hi ,

|A
|
|-B------------------------------------|E
|.
|
|
|---------------------------------------|D
C

Draw a rough diagram ,

Join D , E .

And join A to D and A to E .

Now ,

Height of the tower = AC = 50m

Height of the pole = DE = h m

CD = BE = x m

< AEB = 45°


i ) From ∆ ACD ,

tan
tan 60° = 50/x

√3 = 50/x

x = 50/√3 ---( 1 )

ii ) from ∆ AEB ,

tan
tan 45° = AB/x

1 = AB / x

x = AB

Height of the pole = DE

= AC - AB

= 50 - x

= 50 - 50/√3

= 50 ( 1 - 1/√3 )

= 50 ( √3 - 1 )/√3 m

I hope this helps you.

: )

Answer 2

Answer:

hope you get it mark brainliest