from the top of the tower 60 metres high the angle of depression of two objects do north and due south of the tower are 60 degrees and 45 degrees then the distance between two objects is
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Answer:
The distance between the two objects is 94.64cm.
Step-by-step explanation:
Here a = 45° and b = 60°
AD = 60m
angle EAB = angle DBA = a
angle FAC = angle CDA = b
tan a = AD/BD
tan 45° = 60/BD
1 = 60/BD
BD = 60m
tan b = AD/CD
tan 60° = AD/CD
√3 = 60/CD
CD = 60/√3
CD = 60/1.732
CD = 34.64m
Distance between the two objects = BD + CD
Distance = 60 + 34.64
= 94.64m
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