From the top of tower 100 m high a ball is dropped and at the same instant another ball is projected vertically upwards from the ground so that it.just reaches the top of tower. At what height do the balls pass one another
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100-x=1/2gt²...(1)
x=ut-1/2gt²....(2)
u=√2gh...(3)
By solving these equations we got x=75
x=ut-1/2gt²....(2)
u=√2gh...(3)
By solving these equations we got x=75
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