Question

From the traingle ABC given , write down the values of

i) Sin A
ii) Cos A
iii) Tan A
iv) Sin²A + Cos²A ​

Answer 1

This is the answer for your question.

Hope this may help you.

Answer 2

Step-by-step explanation:

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ABC is a right angled traingle

Given

AB = 3

AC = 5

:. By Pythagoras Theorem ,

AB² + BC² = AC²

→ BC² = AC² - AB²

→ BC² = ( 5 )² - ( 3 )²

→ BC² = 25 - 9

→ BC² = 16

→ BC = √16

→ BC = 4

$\bf\underline\green{i)~Sin~A}$

Sin A = $\frac{opposite~side~to~A}{hypotenuse}$ = $\frac{4}{5}$

$\bf\underline\green{ii)~Cos~A}$

Cos A = $\frac{adjacent~side~of~A}{hypotenuse}$ = $\frac{3}{5}$

$\bf\underline\green{iii)~Tan~A}$

Tan A = $\frac{opposite~side~of~A}{adjacent~side~of~A}$ = $\frac{4}{3}$

$\bf\underline\green{iv)~{Sin}^{2}{A}{+}{Cos}^{2}{A}}$

Sin²A + Cos²A = $\frac{4}{5}^2{+}\frac{3}{5}^2$

→ $\frac{16}{25}{+}\frac{9}{25}$

→ $\frac{16 + 9}{25}$

→ $\frac{25}{25}{=}{1}$

:. Sin²A + Cos²A = 1

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