Question

from the velocity time graph given below calculate: (1)acceleration along ab. (2)Acceleration along bd. (3)total distance travelled.​

Answer 1

Explanation:

sorry for answer 3.

I hope 1 and 2 will helped you

Answer 2

Answer of each part is given below .

Given :

Graph between velocity( V ) and times ( t ) .

In case 1 .

We need to find the acceleration along ab .

We know , acceleration is change in velocity per unit time .

$a_{ab}=\dfrac{40\ m/s}{2\ s}\\\\a_{ab}=20\ m/s^2$

In case 2 .

We need to find the acceleration along bd .

Here , in ab the velocity along bd is constant .

Therefore , acceleration along bd is zero .

In case 3 .

We need to find the total distance covered .

Now , total distance covered in V vs t graph is the area under the curve .

Here , distance = area under the trapezium ABDE .

$D =\dfrac{1}{2}(Sum \ of\ parallel\ sides )\times (perpendicular \ height )\\\\D=\dfrac{1}{2}\times (4+8)\times 40\\\\D=240\ m$

Hence , this is the required solution .

Learn More :

Kinematics

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