Question

From the vertex of a tower the angle of depression of a point 150metres away from the foot of a tower is 60.find the height

Answer 1

this is the answer

here we are given the distance of point from the foot of the tower

and we have to find the height of the tower

hope it helps you alot

Answer 2

Given is the angle of depression and the distance of the foot of a tower from a point on the ground, find the height of the tower.

Explanation:

• Visualizing the scenario given here we get that the top of the tower, the foot of the tower, and the point on the ground form a right-angled triangle.
• Now the angle of depression at the top of the tower is equal to the angle of elevation at the point on the ground that is $\theta$.
• Now w.r.t the angle of elevation, the perpendicular length is the height of the tower.   $->P=h$
• The base length is the distance from the foot of the tower to the point on the ground.  $B=150\ m$
• Hence, we have
•                           $tan\theta= \frac{P}{B}\\ ->tan(60)=\frac{h}{150} \\->h=\sqrt{3} (150) \\->h\approx 260\ m$    
• The height of the tower is nearly $260\ m$.