From this 2u+at/2=s/t how this came ut+1/2 at^2 = s
Answers
Answered by
2
Hey mate here is your answer:
s = ut + 1/2 at^2
Let the distance travelled by the body be “s”.
As
Distance = velocity X Time
Also, Average velocity = (u+v)/2
.: Distance (t) = (u+v)/2 X t …….eq.(1)
As :
v = u + at
substituting this value of “v” in eq.(2), we get
s = (u+u+at)/2 x t
=>s = (2u+at)/2 X t
=>s = (2ut+at^2)/2
=>s = 2ut/2 + at^2/2
or s = ut +1/2 at^2
This is the 2nd equation of motion.
Hope u got it. Do follow for more queries
s = ut + 1/2 at^2
Let the distance travelled by the body be “s”.
As
Distance = velocity X Time
Also, Average velocity = (u+v)/2
.: Distance (t) = (u+v)/2 X t …….eq.(1)
As :
v = u + at
substituting this value of “v” in eq.(2), we get
s = (u+u+at)/2 x t
=>s = (2u+at)/2 X t
=>s = (2ut+at^2)/2
=>s = 2ut/2 + at^2/2
or s = ut +1/2 at^2
This is the 2nd equation of motion.
Hope u got it. Do follow for more queries
Similar questions