Question

from this:
(a+b+c)³ = a³ + b³ + c³ + 3 (a+b) (b+c) (c+a)
derive this:
(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)−abc]

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Answer 1

Step-by-step explanation:

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