From top of a building 125 m high a ball is thrown horizontally with speed 10 m/s. the time taken by it to reach the ground is.(take g=10 m/s² ) *
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Answered by
73
Given :
▪ Height of building = 125m
▪ Initial horizontal velocity = 10mps
▪ Acc. due to gravity = 10m/s²
To Find :
▪ Time taken by ball to reach at the ground.
Solution :
☞ This question is completely based on the concept of Height to Ground projectile motion.
☞ In this type of motion, time taken by object to reach at the ground depends only on vertical motion.
☞ Initial velocity for vertical motion = zero
☞ Horizontal component of velocity remains constant throughout the motion but vertical component of velocity doesn't remain constant as gravitational acceleration acts in the downward direction continuously.
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42
Given:-
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To find:-
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Required Solution:-
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