Question

from top of a tower the angle of depression of top and bottom of am multistoreyed building are 30° and 60° respectively. if the height of the building is 100m . find the height of the tower​

Answer 1

Step-by-step explanation:

Let AC=h be the height of the tower.

and ED be the multi-storeyed building, where ED=100m

So, ED=BC=100m

So, AB=(h−100)m

In ΔABE,

tan30

o

=

EB

AB

⇒

3

1

=

EB

h−100

⇒EB=

3

(h−100) .... (i)

So, DC=EB=

3

(h−100)

In ΔADC,

tan60

o

=

DC

AC

=

3

=

3

(h−100)

h

⇒3(h−100)=h

⇒3h−300=h

⇒2h=300

⇒h=150 metres

Thus, the height of the tower is 150 m.

#yourbuddyworstXx