Question

from top of building 50m tall on object on the ground seen at angle of depression of 30° find the distance of the object from the foot of the building​

Answer 1

Answer: 28.87m

Step-by-step explanation:

Let's take the building to be AB and the point where the person is standing to be C. If we join ABC we will get a triangle.

Now given that AB = 50m

We know that tanθ = perpendicular/base

Here θ is the angle of the point ok view

So,

tanθ = AB/BC

or tan30° = 50/BC

or 1/$\sqrt{3}$= 50/BC

or 50/$\sqrt{3}$ = BC

Therefore the required distance is 50/$\sqrt{3}$m or 28.87m