from transformations show that sin 78⁰-sin18⁰+cos132⁰
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sin A cos B - cos A sin B = sin ( A - B )
so sin (78-18)= sin 60 =√3/2
Explanation @::
Given Equation is in the form of sin A cos B - cos A sin B.
We Know that sin A cos B - cos A sin B = sin (A - B).
Here A = 78, b = 18.
Therefore sin 78 cos 18 - cos 78 sin 18 = sin(78 - 18)
= sin 60.
= root 3/2.
Hope this helps!
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