Math, asked by Sukhdeep75301, 1 year ago

From two places, 60 km apart, A and B start towards each other at the same time and meet each other after 6 hour. If A traveled with 2/3 of his speed and B traveled with double of his speed, they would have met after 5 hours. The speed of A is:
A.4 km/h
B.6km/h
C.10 km/h
D.12 km/h

Answers

Answered by Anonymous
6
ĀNSWĒR ⏬⏬


B.6km/h

✔A to B 60km
Let the speed of A= x kmph and that of B = y kmph;

According to the question;
X*6+y*6 = 60
Or, x+y = 10 --------- (i)

And, 


{(2x/3)*5}+(2y*5) = 60

Or, 10x+30y = 180;

Or, x+3y = 18; ---------- (ii)

From equation (i)*3 - (ii)


3x+3y-x-3y = 30-18
Or, 2x = 12

Hence, x = 6 kmph.✔✔✔✔


THANKS ✌✌✌✌
Answered by Anonymous
4
ĀNSWĒR ⏬⏬

B.6km/h


Let the speed of A= x kmph
B = y kmph;

According to the question;

X*6+y*6 = 60
Or, x+y = 10 --------- (i)

And, 

{(2x/3)*5}+(2y*5) = 60
Or, 10x+30y = 180;
Or, x+3y = 18; ---------- (ii)
From equation (i)*3 - (ii)
3x+3y-x-3y = 30-18
Or, 2x = 12
therefore,
x = 6 kmph.


THANKS ❤:)


#Nishu HARYANVI ♠
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