From velocity-time graph we can find
the displacement of the body.
acceleration of the body.
displacement velocity and acceleration of the body
none of these.
Answers
(i) Acceleration of a body
(ii) the displacement of a body and
(iii) the distance traveled in a given time
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ANSWER
The Velocity-Time graph gives the change of velocity with the change in time
Y-Axis: Velocity
X-Axis: Time
Now, the slope of the velocity-time graph is given as
Slope=
Δx
Δy
=
Δt
Δv
Since, y=v (Velocity)
And x=t (time)
Now, there are three types of Velocity-Time graph
(a) Velocity is constant-Uniform Motion
this means that velocity remains the same for all time
(b) Uniformly Accelerated Motion
This means that velocity changes at a constant rate
Slope = Constant and the graph is a straight-line graph
(c) Non-Uniformly Accelerated Motion
This means that velocity changes at a variable rate
Slope = Variable and the graph is as shown
Velocity-Time graph can be used to find the following as:
(a) Acceleration:
The slope of Velocity − Time Graph=Acceleration
Since Slope=
Δt
Δv
So, Acceleration
Δt
Δv
And hence, Slope = Acceleration
(b) Displacement of a body
The area under the velocity − Time graph gives the displacement of the body
Displacement = Velocity × Time
The area under the graph = Displacement of body
For finding the area, we multiply the velocity and time
(c) The distance of body:
Distance = Speed × Time
Now, Speed its magnitude of the velocity
Hence as long as the velocity is positive,
The area under the curve = Distance
NOTE:
If velocity is negative, then the area under the curve is negative and then the total area gives the displacement. So, in that case
Distance
= Displacement
Example: Let the velocity-time graph be as shown below:
Now Displacment= Area under the curve
=
2
1
×5×2−
2
1
×5×2+
2
1
×5×2=5m
Whereas Distance =
2
1
×5×2+
2
1
×5×2+
2
1
×5×2=15m
For displacement, we have considered the area below the time axis as negative whereas, for distance, we have considered all areas as positive like this answer plz follow me