Physics, asked by Chandan95591, 1 month ago

from what height should a car be dropped to gain the same kinetic energy it would have if it we're moving horizontally at 95 km/hr

Answers

Answered by mahanteshgejji

3

Answer:

The PE at top = KE at horizontal

Explanation:

mgh = 1/2mv2

v=95km/hr= 95x5/18 = 26.38m/s

h =v2/2g = 26.38x26.38/2x9.8 = 35.5 m

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