Question

From what value of k , -4 is Zeroes of the polynomial x²-x-(2k+2) ​

Answer 1

Answer:

k = 9

Step-by-step explanation:

f(x) = x² - x - (2k +2)

f(-4) = (-4)² -(-4) - (2k + 2)

0    = 16 + 4 - 2k - 2

0    = 18 - 2k

 2k = 18

   k = 18 ÷ 2

∴ k = 9