From which expression must 2a^2 + 6a – 3 be subtracted to obtain a difference of a^2 + a + 1? A. 3a^2 + 7a – 2 B. 3a^2 – 7a – 2 C. 3a^2 – 7a + 2 D. 3a^2 + 7a + 2
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Answer:
Step-by-step explanation:
Let X be subtracted from 3a
2
−6ab−3b
2
Then,
3a
2
−6ab−3b
2
−1−X=4a
2
−7ab−4b
2
+1
x=3a
2
−6ab−3b
2
−1−(4a
2
−7ab−4b
2
+1)
x=3a
2
−6ab−3b
2
−1−4a
2
+7ab+4b
2
−1
x=−a
2
+ab+b
2
−2
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