From your initial position x = -3.7 m, you walk 5.8 meters in the positive direction and then walk 6.3 meters in the negative direction. What is your current position?
Answers
Explanation:
Position
To describe the motion of an object, you must first be able to describe its position (x): where it is at any particular time. More precisely, we need to specify its position relative to a convenient frame of reference. A frame of reference is an arbitrary set of axes from which the position and motion of an object are described. Earth is often used as a frame of reference, and we often describe the position of an object as it relates to stationary objects on Earth. For example, a rocket launch could be described in terms of the position of the rocket with respect to Earth as a whole, whereas a cyclist’s position could be described in terms of where she is in relation to the buildings she passes (Figure). In other cases, we use reference frames that are not stationary but are in motion relative to Earth. To describe the position of a person in an airplane, for example, we use the airplane, not Earth, as the reference frame. To describe the position of an object undergoing one-dimensional motion, we often use the variable x. Later in the chapter, during the discussion of free fall, we use the variable y.
Displacement
If an object moves relative to a frame of reference—for example, if a professor moves to the right relative to a whiteboard (Figure)—then the object’s position changes. This change in position is called displacement. The word displacement implies that an object has moved, or has been displaced. Although position is the numerical value of x along a straight line where an object might be located, displacement gives the change in position along this line. Since displacement indicates direction, it is a vector and can be either positive or negative, depending on the choice of positive direction. Also, an analysis of motion can have many displacements embedded in it. If right is positive and an object moves 2 m to the right, then 4 m to the left, the individual displacements are 2 m and −4−4 m, respectively.
Displacement
Displacement ΔxΔx is the change in position of an object:
Δx=xf−x0,Δx=xf−x0,
where ΔxΔx is displacement, xfxf is the final position, and x0x0 is the initial position.
We use the uppercase Greek letter delta (Δ) to mean “change in” whatever quantity follows it; thus, ΔxΔx means change in position (final position less initial position). We always solve for displacement by subtracting initial position x0x0 from final position xfxf. Note that the SI unit for displacement is the meter, but sometimes we use kilometers or other units of length. Keep in mind that when units other than meters are used in a problem, you may need to convert them to meters to complete the calculation (see Conversion Factors).
Objects in motion can also have a series of displacements. In the previous example of the pacing professor, the individual displacements are 2 m and −4−4 m, giving a total displacement of −2 m. We define total displacement ΔxTotalΔxTotal, as the sum of the individual displacements, and express this mathematically with the equation
ΔxTotal=∑Δxi,ΔxTotal=∑Δxi,
where ΔxiΔxi are the individual displacements. In the earlier example,
Δx1=x1−x0=2−0=2m.Δx1=x1−x0=2−0=2m.
Similarly,
Δx2=x2−x1=−2−(2